Digi 207/240 Help

[AznDragon2004]

This is on Boolean Reduction

A + not A*B + not B*C + A*C

I'm not sure where to start.

[dj_honda]

ok well heres what i would start off with. i havent done this for 1.5 years so forgive me if i am off/ dont go as far as you require:

A + A'B + B'C + AC
is your eqn.

so you go like this, take the first 2 components:

A + A'B = (A + A')(A + B)
however, A+A' = 1
so the first 2 components are the same as A + B

so your eqn now sits as:

A + B + B'C + AC

now you can simplify this using the same method above as follows:

B + B'C = (B + B')(B + C)
which = B+C

so your total eqn now is :

A + B + C + AC

you can simplify the first and last 2 components or the first and last components by just going 1 + x if you want. there may be a way to go further but i am too lazy lol. just look at the rules and you might find another one that will work. good luck.

[AznDragon2004]

You got pm

[AznDragon2004]

Anyone else here able to help me?

[V6-BoI]

Originally posted by AznDragon2004
Anyone else here able to help me?

So that solution is wrong?

[koopkoop2]

Have you tried reading the text book yet? There's alot of samples and I'm sure you can pick through enough of them to get the solution for that problem.

Oh yeah, you should also tell us if that solution was wrong.

[AznDragon2004]

I figured it out myself. :)

Thanks for your help though