Induced current problem.

[tbomb]

A circuit consists of a flashlight bulb, rated 3.0V/1.5W, and ideal wires with no resistance. The right wire of the circuit, which is 10cm long, pulled at constant speed v through a perpendicular magnetic field of strength 0.10T.
What speed must the wire have to light the bulb to full
brightness?

-Using, I=vLB/R and P=(V^2*L^2*B^2)/R

v= velocity L=length B=magnetic field R=resistance V=potential

-Then v= sqrt((P*R)/(L^2*B^2)) <- would be used for solution, but R is needed

-So, I=P/ΔV and R= ΔV/I, where P=power

Now, R=6ohms

When i plug numbers in a get a solution of v=300m/s.
Does this seem right? Dont have answers, and 300m/s seems really fast.

[tbomb]

--------------------------------------------
| \
| \
| \--------------------->v
| Right wire
Bulb \
| \
| \
| \
------------------------------------------------

[rinny]

Did you convert your length to meters??

[adubs]

300m/s is correct. It's a slidewire generator and the high velocity required is one of the reasons why they aren't feasible, the other being that there is a limited range of motion.