Math Question

[2BLUE]

Right now we are using a diesel fuel transfer pump.

The pump is not strong enough to pump 10 feet straight up and into a holding tank.

How do i figure out the "math" on which pump i need?

We have tried using 15 GPM and 20 GPM transfer pump and still a no go. (But this is volume going out) (We need suction volume)

I even tried the pump on my tidy tank and reversed the polarity and there's not that much suction.

Fill Rite doesnt have the suction discription so im alittle lost here errr

[CompletelyNumb]

Unless my math is wrong, that's only 4 psi pushing back on the pump :dunno: I'm surprised it can't handle it.

[SKR]

Your math is right, unless mine is wrong too.

10 feet is 3.048m, diesel's density is 840kg/m3.

3.048 x 0.00981 x 840 = 25kPa

25kPa x 0.145 = 3.64psi.

[BlackArcher101]

Are you placing the pump near the holding tank, thus needing much more suction lift than the output lift?

The suction head a pump has is usually a fraction of the output head. It's always best to place a pump as close as possible to the source of the fluid, or in this case 10ft below the holding tank.

Where is your pump located? 10ft of suction is actually quite a bit for a pump to handle, but 10 ft of output shouldn't be a problem.

[Abeo]

10 feet up from pump outlet to hose outlet = 10 feet of head, which means there is a 10 foot column of fluid that the pump has to overcome. You can convert between the 'rated' psi and the head

P (pressure) = density x gravitiational constant x height (head)
(same thing that SKR posted)

Generating pressure at the outlet of a pump (transfer pump on the ground) is a heck of a lot easier than using a pump to suck fluid up (transfer pump 10 feet up, trying to suck from something on the ground)