Math Problem Help

[AznDragon2004]

How would you do this problem??? It's on Conics.


Ax^2 - y^2 + Dx + Ey + F = 0

I don't know how to get started on this problem.

Also how would i enter the function sec (x) in my calculator??? I know that SEC is also COSINE.

I'll appreciate if someone helps me.

[V6-BoI]

What is the question for the conics problem?

And SEC is not COSINE, SEC is 1/COS
so sec(x) = 1/cos(x) or (cos(x))^-1 whatever you perfer.

[roopi]

http://hometown.aol.com/jpr2718/ax2p.pdf

Check that out. It may help you out some. :dunno:

[AznDragon2004]

The conics problem is this:

Ax^2 - y^2 + Dx + Ey + F = 0

with 4 choices:

A. A = 3 B. A = 0 C. A = -3 D. A = -5

I'm not sure how u get the answer.

[AznDragon2004]

It also says:

For which of the following values of A will the equation Ax^2 - y^2 + Dx + Ey + F = 0 be a hyperbola???

[Gondi Stylez]

im pretty sure its b. a=0

because i think for it to be a hyperbola y must be negative and x must equal 0!

[blinkme_210]

Originally posted by AznDragon2004
The conics problem is this:

Ax^2 - y^2 + Dx + Ey + F = 0

with 4 choices:

A. A = 3 B. A = 0 C. A = -3 D. A = -5

I'm not sure how u get the answer.

U don't need to know how to do the question to solve it. You have should known the basic A & C rules to find out what kind of graph it is, it's the basis of the whole unit of conics.....