If you cant solve it, you are stupid

[M68KACIA]

Hey guys try this:

http://www.transience.com.au/pearl.html

(The HARDEST GAME in the history of mankind)

[bosa]

dude thats hard,i'm still trying to beat him...i think it might be impossible. :dunno: but you can't leave 2 pearls in 2 rows..

[bosa]

after playing for several minutes,its I-M-P-O-S-S-I-B-L-E...

[redec]

it's really quite easy if you understand the math behind it....I win every time....

[bosa]

how do you win? :dunno:

[redec]

there's also this one.....little harder, but the math still works http://www.transience.com.au/pearl2.html

[redec]

Originally posted by civicLVR
how do you win? :dunno:


I'll let some other people play before posting the spoiler :P

[Hakkola]

Tried the 2nd one, I've never been so annoyed by losing, that laugh...

[theken]

impossible as trying to fuck a 400 lb chick

[bosa]

Originally posted by redec



I'll let some other people play before posting the spoiler :P

i think enough people are pissed by this game,tell us..:D

[redec]

ok....this is the simplest way I can figure how to explain it...

you have to think in binary....each row is a binary number....5 pearls is 101, four is 100, 3 is 011....take these numbers and treat them as decimal, and add them together (212)...this sum is the important number...at the end of your turn, you always want every digit in the sum to be an even number.....so, 212 is not a good number because it has a 1 in it, so you can change that 1 into a 0 by getting rid of 2 of the pearls on the line with 3 pearls...so the numbers become 101+100+001=202....continue this way until you're out of pearls....works every time

[theken]

Originally posted by redec
ok....this is the simplest way I can figure how to explain it...

you have to think in binary....each row is a binary number....5 pearls is 101, four is 100, 3 is 011....take these numbers and treat them as decimal, and add them together (212)...this sum is the important number...at the end of your turn, you always want every digit in the sum to be an even number.....so, 212 is not a good number because it has a 1 in it, so you can change that 1 into a 0 by getting rid of 2 of the pearls on the line with 3 pearls...so the numbers become 101+100+001=202....continue this way until you're out of pearls....works every time what the fack??:dunno: :dunno:

[Stratus_Power]

ok yeh that guy is pissingme off too

[theken]

I did it my own way and it worked pimped!! I owned that mofo

[redec]

Originally posted by theken
I did it my own way and it worked pimped!! I owned that mofo

try the one with 4 lines :P

[theken]

http://www.transience.com.au/eieio.html this one is stupid hard too

[theken]

i tried the one with 4 lines he owned me

[Stratus_Power]

i still dont get wat u mean .... so i take out 2 in the row w/ 3.. wats next?

[redec]

Originally posted by theken
http://www.transience.com.au/eieio.html this one is stupid hard too


heh....I got it second try :P...I've seen a similar one before tho

[redec]

Originally posted by Stratus_Power
i still dont get wat u mean .... so i take out 2 in the row w/ 3.. wats next?


depends on what he does.....recalculate using the same algorythm, and get rid of as many pearls as needed to make every digit in the sum even....

[theken]

i never gave it a second try. :tongue:

[Si_FlyGuy]

Can you put this in terms of debits and credits for the non-compsci accounting crowd? hehehe

Okay..what are the binary values for the numbers 1-5? That'll make it easier to understand.

[redec]

not really....the first thing I said was that was the simplest way I could think of to explain it....it's quite hard to give a non-technical solution to an extremely technical problem :P

[Si_FlyGuy]

Wait..I guess I just need the binary equivalents for "1" and "2"...

[RiCE-DaDDy]

com sci nerds only!

[Davetronz]

I got upset and unplugged my speakers...

[speedracer]

Originally posted by redec

you have to think in binary....this sum is the important number...at the end of your turn, you always want every digit in the sum to be an even number.

lol I saw it the same way. Somehow that's actually scaring me... :eek:

[Si_FlyGuy]

Phew finally got it...good thinking guys...what made you first associate binary codes with this??


That vampire dude is http://members.shaw.ca/fivegluder/Pictures/Untitled-1.gif

[redline_13000]

fukin guy pissses me off!!!!

[speedracer]

Originally posted by Si_FlyGuy
Phew finally got it...good thinking guys...what made you first associate binary codes with this??


Well, first I tried to group the rows and make the values even but then I put it in a matrix and the binary sum worked. I didn't see it right away like Reduc. It wasn;t until my 4 try at it did I see the pattern.

[Si_FlyGuy]

I played the second one, and tried to mirror the moves that the vampire guy was making in the first one to figure out how to counteract, since you can allow the vampire to start first in the second one. Then I went back to the first one and figured it out from there...but the binary method's a lot easier.

[got M]

.

[boi-alien]

done and done... pretty easy

[RickDaTuner]

Yeah i beat him too

[James]

I have no clue WTF Redec is talking about....I have found atleast 5 combos that i know DONT work...the guys laughing is so fucking annoying...its 6:00am...Im tired...But i cant stop trying to beat this!

[Heep]

Geez Murph!

I want to take those pearls and shove them down that arsehole's throat...

OK...so anyways, this binary thing isn't workin for me...I keep changing my sum to all even numbers but he still hoses me, it's pissing me off. Is there a walkthrough or something, lol I don't care if I figure it out or not, I just want to beat it so I can laugh at him back

[Redlyne_mr2]

Originally posted by Heep
Geez Murph!

I want to take those pearls and shove them down that arsehole's throat...

OK...so anyways, this binary thing isn't workin for me...I keep changing my sum to all even numbers but he still hoses me, it's pissing me off. Is there a walkthrough or something, lol I don't care if I figure it out or not, I just want to beat it so I can laugh at him back
Mark you'll never take him out...I saw how you did on those dms exams, your brain is beat:D

[Melinda]

Yeah! I finally beat him! HEHEHE keep trying guys, the look on his face when he loses is very worth it! (Don't ask how I did it cause I can't remember) :D

Melinda

[Si_FlyGuy]

Haha..take two from the row of three, then take two from the row of 5...figure it out from there hehehe

[Heep]

Originally posted by Redlyne_mr2

Mark you'll never take him out...I saw how you did on those dms exams, your brain is beat:D

Haha yeah, my brain went into chillin mode once I got home, I can't think now :nut:

[Alain]

Here is the solution for Pearl 2! (http://www.ebaumsworld.com/pearl.shtml)

I am not a mathematician, I just tried to see what he is doing when he starts. The most easiest way to beat him is THAT YOU START. Out of 6 5 4 3 make 6 5 0 3. Then see what he does. Leave him even 5-4-1 or 3-2-1 or (important) leave him to rows with the same number of pearls. Eg. 5-5 or 4-4 or 3-3 or 2-2. The most tricky thing is when he leaves you 6 5 0 2. Then just make 6 4 0 2 and he will lose again! Any questions? Best regards, Alain



www.vuagneux.ch

[QuasarCav]

Is this a record for oldest thread bumped?

[Alain]

My English is limited. I just tried to give a summary of what I read and my own experiences. I think my description is simple and easy. Nothing to do with mathematics and bionary systems.

Carpe Diem

[Dustin Mann]

Ok so the first two parts are easy enough using the binary summation system. Her'es where it gets really tough. Playing Part III

http://www.transience.com.au/pearl3.html

Once you get to the third level, the bastard starts you out with 3, 8, 11. Binary equivelents are 11, 1000, 1011 . The sum is 2022.. he's starting you with a sum where each digit is an even number. There is no way to leave him with an even digit sum. What do you do? :dunno:

Has anyone beat Part III level III??

If you have then you are my here :thumbsup:

[Dustin Mann]

:eek: i guess you have to wait til he sets it up as 5-8-10 for level 3. pretty stupid that they have an unbeatable one.

[sputnik]

It's a classic game... we had to write a program that played against you when I was in CompSci.

Redec is dead on with his explanation.

[subdermal]

part 3 level 3:

you go first. leave him:
2-8-10
he will leave:
2-3-10
you: 2-3-1
him: 1-3-1
you: 1-1-1
him: 1-0-1
you: 0-0-1
done.

[Dustin Mann]

yep. got it. I'm on level 22 now

[subdermal]

Heh I got bored at 13. What I still can't figure out is why such a simple question (how to make the opponent take the last pearl) has such a complicated answer. I have a feeling that the binary method is sorta the long way around, but haven't found a simpler answer. You should be able to do it by just looking at the arrangement of the pearls, I would think.

[Dustin Mann]

well. once you get two rows, if they're the same length at the end of each turn then you're good. same goes for four rows. additionall if two of the rows are one length, and the other two another length at the end of your turn, then you're good. There's a bunch of other similar patterns but of course they're all operating on the doubling a binary number in the decimal system will give you an all even digit number. I'm on level 26 now, I just want to reach the end because i can't save my progress. IS THERE AN END??? there's 7 rows of like 24 now.
:whocares:

[Dustin Mann]

well. you can stop guessing. there's 28 levels. finally done:closed:

[subdermal]

yeah if you can give him only pairs of matched rows you will win. Plus any odd number of rows of only one. Also if you can give him a 3,2,1 or if you can give him 3 rows of 1,x,y where [x-y=|1| & x>3 & y>3] (because from that you can get to a matched pair guaranteed).

I still can't figure out an easily visible pattern that shows the right move for any given arrangement though.

[redec]

Originally posted by Dustin Mann
well. you can stop guessing. there's 28 levels. finally done:closed:

um....dunno what kinda drugs you're on....I played it to level 31 and it was still going...stopped cuz I got bored of it...had a 100% winning percentage....