I have a math upgrade test at sait on thrusday n i need help on these question havent taken math since last semester so i forgot some of this shit. Hope u can help me out its number 40 n 41 thanx lots
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I have a math upgrade test at sait on thrusday n i need help on these question havent taken math since last semester so i forgot some of this shit. Hope u can help me out its number 40 n 41 thanx lots
http://www.manifestation.org/~ill/im...antseeshit.jpgQuote:
Originally posted by civic_rida
I have a math upgrade test at sait on thrusday n i need help on these question havent taken math since last semester so i forgot some of this shit. Hope u can help me out its number 40 n 41 thanx lots
yea its beging gay
yo
D & B
whats so hard about it.. you just multiply it out ( the answers) and see if it make sense
like m^2 X 144m^7 doesnt take alot of math skill to do
Quote:
Originally posted by Weapon_R
D & B
:werd: , comon justin; its only math applied :D
man i dont miss high school......iam sure i did that back in the day, looks confusing.
41 seems like u dont do anything just put the number together
Someone tell me how to do 40
the answer just happens to be like that..Quote:
Originally posted by civic_rida
41 seems like u dont do anything just put the number together
best way to learn through that 2 questions is to work out each answer and see which one matches the question.
if you do that to Q41 you will find out a, c and d doesnt equal to the given equation
if you are multiplying the power together ( ie X ^ 4, 4 is the power.) then you jsut add the 2 powers together.
so for example
16m X 2m^2
16 X 2 is 21
m X m^2 = m^3 cuz you are adding the power together..
or if your question is how would you get the answer if its not m-choice..
then all you do is look and see if anything is in common w/ each set of numbers.
ie .. they all have [m] to the power of something..
so you take out the lowest power.. m^2.. bring it to the front and subtract m^2 to all the numbers.. same w/ the integers
still dont c how it relates to the top 144m9-160m7-96m2
16m^2(9m^7 - 10m^5 - 6)
you just multiply each one out. .this is Jr high concept
16m^2 X 9m^7 = (16X9) ( m^2 X m^7)
16X10.. simple enuf
( m^2 X m^7).. since its multiply.. you ADD the power together..
7+2 = 9..
you do that to 16m^2 X 10 M^5 and 16m^2 X 6
etc..
and since it is minus.. you keep the minus.. and voila.
the common factor is the one number that can be applied to all the other numbers in the equation, theres only one answer being d because you can take 16m^2 out of each number, the other two (b and c) do share a common factor but your missing the other common factors aswell (your trying to break down an equation as much as possible)...hope i made some sense blah haaha
if u chose 16 as a common factor your missing that you can also take out m^2
and vice versa
so it only makes sense to pick the answer with a common factor of both 16 and m^2, therefore 16m^2 DUH!
so is that list of numbers like 144 so on just a example?
144, 160, and 96 as you can see can be broken down by 16 as an example...it could be 8, 6, and 4 for all it matters, the common factor being 2...no diff
u factor out the most common pairing, ok the answer is D: 16m2 (9m7 -10m5 -6)Quote:
Originally posted by civic_rida
still dont c how it relates to the top 144m9-160m7-96m2
16m2 is being factored out from the original numbers (144m9-160m7-96m2)
16m2 goes into 144m9; 9m7 times
16m2 goes into 160m7; 10m5 times
16m2 goes into 96m2; 6 times
so u put the largest factored number outside the brackets (16m2) and the new multiples i just showed u on the inside (9m7 -10m5 -6)
So ur lookin for a common factor so that leaves c , d , but d has the common factor of 2 also thank alot dude u helped me tons.
booooyaaaaa ic it