help math 31 question

[AzN'SKillZ]

i missed the lesson on one sided limits, and i have a test soon plz help!!!!!

lim x^2-64/(x-8)^1/2
x-->8^+

EDIT**

[Evolize]

what the fuck do those numbers mean?

[suen17]

everything makes sense up unit x-->8^-

[heinz256]

Originally posted by suen17
everything makes sense up unit x-->8^-

I think he meant as x approaches 8 from the left

[AzN'SKillZ]

**I think he meant as x approaches 8 from the right**
**edit**

so i reduced the question too (x+8)(x-8)^1/2

[jav_]

yeh...wth is 8 to the exponent +?

[AzN'SKillZ]

Originally posted by jav_
yeh...wth is 8 to the exponent +?

as x approaches 8 from the right

this is a one sided limits question

[seer_claw]

Factor the top of the equation. So you get (x+8)(x-8)

now you equation should look like

(x+8)(x-8)/(x-8)^1/2

You can further simplify this by dividing (x-8)/(x-8)^1/2 = (x-8)^1/2 This is just rules of powers, subtract the powers if the bases are equal.

This leaves:

lim (x+8)(x-8)^1/2
x->8

Plug in 8 and you get an answer =0.


Easy.

[msommers]

Take a look at the numerator of this equation: X^2 - 64. That's the first part.

[AzN'SKillZ]

Factor the top of the equation. So you get (x+8)(x-8)

now you equation should look like

(x+8)(x-8)/(x-8)^1/2

You can further simplify this by dividing (x-8)/(x-8)^1/2 = (x-8)^1/2 This is just rules of powers, subtract the powers if the bases are equal.

This leaves:

lim (x+8)(x-8)^1/2
x->8

Plug in 8 and you get an answer =0.


Easy.

is it actually that easy?

cuz i thou finding one sided limits was different from limits

[blainer]

hey skillz
after multiplying by (x+8)^1/2 on the top and bottom and then simplifying u get (x+8)(x+8)^1/2
u should be able to take it from there
-Blaine

[AzN'SKillZ]

Originally posted by blainer
hey skillz
after multiplying by (x+8)^1/2 on the top and bottom and then simplifying u get (x+8)(x+8)^1/2
u should be able to take it from there
-Blaine

i no how to factor

i need to know how to do one sided limits

**AS X APPROCHES 8 FROM THE RIGHT SIDE**

[jav_]

0

[seer_claw]

Originally posted by AzN'SKillZ
^ is it actually that easy?

cuz i thou finding one sided limits was different from limits

Ya, its like a normal limit but you approach 8 from the positive side. You follow the curve of the graph and only look at the value of y when x is greater than 8. But due to the limit you are looking at really small numbers close to 8. As you move close to the value of 8 you eventually find the value at 8. Realistically plug some other numbers into the equation that are slightly larger than 8, try 8.1, 8.01, 8.001 and so on. They are all larger than 8 but you will see that the closer you get to 8 the closer the value gets to 0. A limit just tells you that you are plugging in a number that is infinitely close to 8.

[AzN'SKillZ]

^ thanks for the help!!!!

im off to do my test now