i missed the lesson on one sided limits, and i have a test soon plz help!!!!!
lim x^2-64/(x-8)^1/2
x-->8^+
EDIT**
i missed the lesson on one sided limits, and i have a test soon plz help!!!!!
lim x^2-64/(x-8)^1/2
x-->8^+
EDIT**
Last edited by AzN'SKillZ; 03-17-2007 at 12:23 PM.
what the fuck do those numbers mean?
everything makes sense up unit x-->8^-
I think he meant as x approaches 8 from the leftOriginally posted by suen17
everything makes sense up unit x-->8^-
**I think he meant as x approaches 8 from the right**
**edit**
so i reduced the question too (x+8)(x-8)^1/2
Last edited by AzN'SKillZ; 03-17-2007 at 12:24 PM.
yeh...wth is 8 to the exponent +?
wh...?
as x approaches 8 from the rightOriginally posted by jav_
yeh...wth is 8 to the exponent +?
this is a one sided limits question
Factor the top of the equation. So you get (x+8)(x-8)
now you equation should look like
(x+8)(x-8)/(x-8)^1/2
You can further simplify this by dividing (x-8)/(x-8)^1/2 = (x-8)^1/2 This is just rules of powers, subtract the powers if the bases are equal.
This leaves:
lim (x+8)(x-8)^1/2
x->8
Plug in 8 and you get an answer =0.
Easy.
Take a look at the numerator of this equation: X^2 - 64. That's the first part.
Ultracrepidarian
is it actually that easy?
Factor the top of the equation. So you get (x+8)(x-8)
now you equation should look like
(x+8)(x-8)/(x-8)^1/2
You can further simplify this by dividing (x-8)/(x-8)^1/2 = (x-8)^1/2 This is just rules of powers, subtract the powers if the bases are equal.
This leaves:
lim (x+8)(x-8)^1/2
x->8
Plug in 8 and you get an answer =0.
Easy.
cuz i thou finding one sided limits was different from limits
Last edited by AzN'SKillZ; 03-17-2007 at 12:43 PM.
hey skillz
after multiplying by (x+8)^1/2 on the top and bottom and then simplifying u get (x+8)(x+8)^1/2
u should be able to take it from there
-Blaine
i no how to factorOriginally posted by blainer
hey skillz
after multiplying by (x+8)^1/2 on the top and bottom and then simplifying u get (x+8)(x+8)^1/2
u should be able to take it from there
-Blaine
i need to know how to do one sided limits
**AS X APPROCHES 8 FROM THE RIGHT SIDE**
0
wh...?
Ya, its like a normal limit but you approach 8 from the positive side. You follow the curve of the graph and only look at the value of y when x is greater than 8. But due to the limit you are looking at really small numbers close to 8. As you move close to the value of 8 you eventually find the value at 8. Realistically plug some other numbers into the equation that are slightly larger than 8, try 8.1, 8.01, 8.001 and so on. They are all larger than 8 but you will see that the closer you get to 8 the closer the value gets to 0. A limit just tells you that you are plugging in a number that is infinitely close to 8.Originally posted by AzN'SKillZ
^ is it actually that easy?
cuz i thou finding one sided limits was different from limits
^ thanks for the help!!!!
im off to do my test now