Math help

[civic_rida]

I have a math upgrade test at sait on thrusday n i need help on these question havent taken math since last semester so i forgot some of this shit. Hope u can help me out its number 40 n 41 thanx lots

[gpomp]

Originally posted by civic_rida
I have a math upgrade test at sait on thrusday n i need help on these question havent taken math since last semester so i forgot some of this shit. Hope u can help me out its number 40 n 41 thanx lots

[civic_rida]

yea its beging gay

[civic_rida]

yo

[Weapon_R]

D & B

[Stratus_Power]

whats so hard about it.. you just multiply it out ( the answers) and see if it make sense

like m^2 X 144m^7 doesnt take alot of math skill to do

[Wildcat]

Originally posted by Weapon_R
D & B

, comon justin; its only math applied

[04blackMAX]

man i dont miss high school......iam sure i did that back in the day, looks confusing.

[civic_rida]

41 seems like u dont do anything just put the number together

[civic_rida]

Someone tell me how to do 40

[Stratus_Power]

Originally posted by civic_rida
41 seems like u dont do anything just put the number together

the answer just happens to be like that..

best way to learn through that 2 questions is to work out each answer and see which one matches the question.
if you do that to Q41 you will find out a, c and d doesnt equal to the given equation

[Stratus_Power]

if you are multiplying the power together ( ie X ^ 4, 4 is the power.) then you jsut add the 2 powers together.
so for example

16m X 2m^2

16 X 2 is 21
m X m^2 = m^3 cuz you are adding the power together..

or if your question is how would you get the answer if its not m-choice..

then all you do is look and see if anything is in common w/ each set of numbers.

ie .. they all have [m] to the power of something..
so you take out the lowest power.. m^2.. bring it to the front and subtract m^2 to all the numbers.. same w/ the integers

[civic_rida]

still dont c how it relates to the top 144m9-160m7-96m2

[Stratus_Power]

16m^2(9m^7 - 10m^5 - 6)

you just multiply each one out. .this is Jr high concept

16m^2 X 9m^7 = (16X9) ( m^2 X m^7)
16X10.. simple enuf
( m^2 X m^7).. since its multiply.. you ADD the power together..
7+2 = 9..

you do that to 16m^2 X 10 M^5 and 16m^2 X 6

etc..

and since it is minus.. you keep the minus.. and voila.

[eur0]

the common factor is the one number that can be applied to all the other numbers in the equation, theres only one answer being d because you can take 16m^2 out of each number, the other two (b and c) do share a common factor but your missing the other common factors aswell (your trying to break down an equation as much as possible)...hope i made some sense blah haaha


if u chose 16 as a common factor your missing that you can also take out m^2

and vice versa

so it only makes sense to pick the answer with a common factor of both 16 and m^2, therefore 16m^2 DUH!

[civic_rida]

so is that list of numbers like 144 so on just a example?

[eur0]

144, 160, and 96 as you can see can be broken down by 16 as an example...it could be 8, 6, and 4 for all it matters, the common factor being 2...no diff

[Wildcat]

Originally posted by civic_rida
still dont c how it relates to the top 144m9-160m7-96m2

u factor out the most common pairing, ok the answer is D: 16m2 (9m7 -10m5 -6)

16m2 is being factored out from the original numbers (144m9-160m7-96m2)

16m2 goes into 144m9; 9m7 times
16m2 goes into 160m7; 10m5 times
16m2 goes into 96m2; 6 times

so u put the largest factored number outside the brackets (16m2) and the new multiples i just showed u on the inside (9m7 -10m5 -6)

[civic_rida]

So ur lookin for a common factor so that leaves c , d , but d has the common factor of 2 also thank alot dude u helped me tons.

[civic_rida]

booooyaaaaa ic it